show that alldfa is decidable

M simulates on w and if M reaches a final state, it accepts. Show that A is Turing decidable. M is clearly a decider since steps 1, 3, and 4 will not create an infinite loop and step 2 calls a decider. TM with a one way infinite tape.

The fundamental tool is the following: Theorem 1. Show that for any infinite language L, L is decidable iff some enumerator TM enumerates L in lexicographic order. An in nite binary sequence is an unending sequence of 0s and 1s. In addition, the complexity analysis of CFL and problem solutions are discussed.

Moreover we obtain additional results concerning the case of finitary AFs. Coskey and J. Do the Problem 4. An amazing website. Palindromes on a DFA. Express this problem as a language and show that it is decidable.

Develop a DFA for the language. Show that E is decidable. Why or why not? Solution: Problem 4. If it contains such a string, pumping up shows infinitely many other strings to be in the langauge.

It follows from the following claim. Theorem: A REX is a decidable language. Given a dfa M. So, this is decidable. Sofya Raskhodnikova; based on slides by Nick Hopper. Every decidable language is Turing-Acceptable.I don't want to reset my password. Since the solution to 7. This textbook survival guide was created for the textbook: Introduction to the Theory of Computation, edition: 3.

The full step-by-step solution to problem: 7. This full solution covers the following key subjects:. This expansive textbook survival guide covers 11 chapters, and solutions. Enter your email below to unlock your verified solution to:. About us. Textbook Survival Guides. Elite Notetakers.

Referral Program. Campus Marketing Coordinators. Log in Sign Up. Forgot password? Register Now. Already have an account? Login here. ISBN: Solution for problem 7. Get Full Solutions. Problem 7. Step-by-Step Solution: Step 1 of 3. Step 2 of 3 Chapter 7, Problem 7. Step 3 of 3. Textbook: Introduction to the Theory of Computation Edition: 3. Other solutions.Some string is accepted by the DFA if reaching to the accept state from the initial state by Ask your question!

Show That Infinite Dfa Is Decidable

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show that alldfa is decidable

Sep 13 AM. Ankit B answered on February 28, Answer: Some string is accepted by the DFA if reaching to the accept state from the initial state by Do you need an answer to a question different from the above? Help us make our solutions better. We want to correct this solution. Tell us more. Was the final answer of the question wrong? Were the solution steps not detailed enough? Was the language and grammar an issue?

We appreciate your Feedback Stay Solved :. Didn't find yours? Ask a new question Get plagiarism-free solution within 48 hours. Review Please. Next Previous. Related Questions. Show that Hello, as a basic introduction to decidability, I have been asked to think about these two questions.

For this, senseBy using our site, you acknowledge that you have read and understand our Cookie PolicyPrivacy Policyand our Terms of Service. Computer Science Stack Exchange is a question and answer site for students, researchers and practitioners of computer science. It only takes a minute to sign up. The proof in the textbook Siper page uses two steps:.

And how it can be done? I know this question may be trivial, but it really bugs me. Any clarification will be appreciated. I've often found that, with problems like these, it's easiest to reason by analogy to software, since anything you can do with a computer you can do with a TM and vice versa with a giant asterisk. In software, you could imagine that you'd want to write a method.

Notice that we're given the DFA as a parameter, since if we don't have it, then there's no way that we can answer the question. It would be like someone saying "I'm hiding a DFA behind my back - can you guess whether it accepts a given string? Since this is something that we can do with a computer, it's certainly something that we can do with a TM.

Given this code, it's probably clearer what the TM you described above would do. There are infinitely many possible choices for what that DFA could look like or what that string could be, but at any one point in time the TM works on just a single string and a single DFA. Sign up to join this community. The best answers are voted up and rise to the top.

Asked 3 years, 6 months ago. Active 7 months ago.

Infinity is bigger than you think - Numberphile

Viewed 1k times. If the simulation ends in an accept state, accept. If it ends in a nonaccepting state, reject. Zhiwei Pan Zhiwei Pan 21 3 3 bronze badges. Active Oldest Votes. Thank you. Sign up or log in Sign up using Google. Sign up using Facebook. Sign up using Email and Password.

Post as a guest Name. Email Required, but never shown. Featured on Meta. Responding to the Lavender Letter and commitments moving forward. Related 3. Hot Network Questions. Question feed.By using our site, you acknowledge that you have read and understand our Cookie PolicyPrivacy Policyand our Terms of Service. Mathematics Stack Exchange is a question and answer site for people studying math at any level and professionals in related fields.

It only takes a minute to sign up. If at any time a non-accepting state is visited, rejectotherwise, if only accepting states are found, accept. My answer to this problem on a recent homework was originally similar to the other answer on this question: Perform a breadth first search on the input, If a non-accept state is visited reject, Otherwise accept.

However, this solution is wrong. The following DFA with an alphabet of 0 and 1 is an example of this. It will not accept inputs with a 1, but there is no reject state that will cause this DFA to be rejected by the decider.

The answer is actually to construct the complement to the input and test whether the language of the complement is an empty set. You can do this by doing a breadth or depth first search on the complement and if an accept state is found, reject the input and otherwise, accept. Sign up to join this community. The best answers are voted up and rise to the top. Home Questions Tags Users Unanswered. Asked 9 years, 6 months ago.

Active 4 years, 5 months ago. Viewed 8k times. Active Oldest Votes. Zach Langley Zach Langley 1, 12 12 silver badges 19 19 bronze badges. But you are correct; I didn't use it in my solution. Sign up or log in Sign up using Google. Sign up using Facebook. Sign up using Email and Password. Post as a guest Name. Email Required, but never shown. Featured on Meta. Responding to the Lavender Letter and commitments moving forward. Related 4.

Hot Network Questions. Question feed. Mathematics Stack Exchange works best with JavaScript enabled.I don't want to reset my password. Since the solution to 7. This textbook survival guide was created for the textbook: Introduction to the Theory of Computation, edition: 3. The full step-by-step solution to problem: 7. This full solution covers the following key subjects:.

This expansive textbook survival guide covers 11 chapters, and solutions. Enter your email below to unlock your verified solution to:. About us. Textbook Survival Guides. Elite Notetakers. Referral Program. Campus Marketing Coordinators. Log in Sign Up. Forgot password? Register Now. Already have an account? Login here. ISBN: Solution for problem 7.

Get Full Solutions. Problem 7. Step-by-Step Solution: Step 1 of 3. Step 2 of 3 Chapter 7, Problem 7. Step 3 of 3. Textbook: Introduction to the Theory of Computation Edition: 3. Other solutions. View Full Material. People also purchased.

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show that alldfa is decidable

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